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Let the three interior angles be x,y and z
angle B
120° +y = 180°
y=60°
angle C
110°+z=180°
z=70°
so, x+y+z= 180°(sum of interior angles of a ∆=180°)
60°+70°+x=180°
x=50°
Hence , x is 50°
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Answer:
Step-by-step explanation:
∠ AEB + ∠ABC = 180 (Linear pair)
120 + ∠ABC = 180
∠ABC = 60
∠ABC + ∠x = 110 (Exterior angle property)
60 + ∠x = 110
∠x = 50
or
∠ACB + ∠ACD = 180 (Linear pair)
∠ACB + 110 = 180
∠ACB = 70
∠ABC + ∠ACB + ∠x = 180 (Angle sum property)
60 + 70 + ∠x = 180
∠x = 180 - 130
∠x = 50
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