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Let b be the breadth
length =b+3
If length and breadth increased by 2cm new area is 70 sq cm more
i.e., b(b+3)+70=(b+2)(b+5)
b^2+3b+70=b^2+2b+5b+10
4b=60
b=15
l=15+3=18.Ans
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Answer:
Let the breadth be b.
length=b+3
area=b(b+3)=b^2+6
If the width is increased
breadth=b+4
If the l is decreased
Length=b-3
area=(b+4)(b-3)=b^2-b+12
A.T.Q.
b^2+6-22=b^2-b+12
b^2-16=b^2-b+12
-16=-b+12
-b=-28
b=28m
l=b+3=31m
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