Math, asked by helenzhimo777, 6 hours ago

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Answered by ritumanishakujur62
0

Answer:

Let b be the breadth

length =b+3

If length and breadth increased by 2cm new area is 70 sq cm more

i.e., b(b+3)+70=(b+2)(b+5)

b^2+3b+70=b^2+2b+5b+10

4b=60

b=15

l=15+3=18.Ans

Answered by akash5732e
0

Answer:

Let the breadth be b.

length=b+3

area=b(b+3)=b^2+6

If the width is increased

breadth=b+4

If the l is decreased

Length=b-3

area=(b+4)(b-3)=b^2-b+12

A.T.Q.

b^2+6-22=b^2-b+12

b^2-16=b^2-b+12

-16=-b+12

-b=-28

b=28m

l=b+3=31m

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