Math, asked by veniyeruva, 2 months ago

step by step explanation please...
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Answered by rheaharish07
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Answer:

a+b)^2 = a^2 + b^2 + 2ab....Here.... (a+b3^1/2)^2 = a^2 + 3b^2 + 2ab3^1/2... Here...On comparing....a^2 +3b^2 = 7 and 2ab3^1/2 = 4 × 3^1/2 ab = 2 so....a = 2/b..(1)equation4/b^2 + 3b^2 = 7....4 + 3b^4 = 7b^2...Put b^2 = t.... 4 + 3t^2 - 7t = 0... 3t^2 - 4t -3t + 4 = 0..3t(t-1) - 4(t-1) = 0..t = 1 or t = 4/ 3...So b = 1 or b= -1 or b = 2/3^1/2... or b = -2/3^1/2...

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