Question

step by step explanation pls..​

Answer 1

Answer:

see the below

Step-by-step explanation:

Sum of opposite angles of a cyclic quadrilateral is 180°

∴ ∠DAB + ∠BCD = 180°

⇒ 95° + ∠BCD = 180°

⇒ ∠BCD = 180° - 95° = 85°

∵ BE || DC

∴ ∠CBE = ∠BCD = 85° [alternate interior angles]

∴ ∠CBF = ∠CBE + ∠FBE

= 85° + 20° = 105°

Now, ∠ABC + ∠CBF = 180° [linear pair]

and ∠ABC + ∠ADC = 180° [opposite angles of cyclic quad]

Thus, ∠ABC + ∠ADC = ∠ABC + ∠CBF

⇒ ∠ADC = ∠CBF

⇒ ∠ADC = 105° [∵∠CBF = 105°]