Question

step by step explanations please.​

Answer 1

Let the no. subtracted be x .

see the picture

Answer 2

${\Large{\underline{\underline{\bf{Question :}}}}}$

What must be subtracted from $6 \dfrac{4}{5}$ to get $1 \dfrac{7}{10}$ ?

${\Large{\underline{\underline{\bf{Answer:}}}}}$

Understanding the question :-

• Here it is given that (6 )4/5 is subtracted by unknown number which will give (1) 7/10. Suppose as example 6 - ___ = 10. Here it is same like that but it is given in form of statement. We need to find value of unknown number.

Assumption :-

• Let's assume unknown number as x .

Given :-

• $6 \cfrac{4}{5}$

• $1 \cfrac{7}{10}$

To find :-

• A number that would be subtracted to get $1 \dfrac{7}{10}$

Solution :-

First we have to make equation such that we can get equal value of LHS and RHS after solution.

${\large{\sf{ \ratio\longmapsto{6 \cfrac{4}{5} \: \: - \: x = 1 \cfrac{7}{10} }}}}$

Converting mixed fraction into simple fraction.

${\large{\sf{ \ratio\longmapsto{ \cfrac{34}{5} \: \: - \: x = \cfrac{17}{10} }}}}$

On LHS side, let's do LCM of 5 and 1. After doing, LCM will be 5. Taking 5 as common on LHS side.

${\large{\sf{ \ratio\longmapsto{ \cfrac{34 - 5x}{5} = \cfrac{17}{10} }}}}$

Cross Multiplication of 5 and 10 with each other.

${\large{\sf{ \ratio\longmapsto{ {10(34 - 5x)}= {5(17)}}}}}$

Further solving the eqation.

${\large{\sf{ \ratio\longmapsto{ 340 - 50x= 85}}}}$

${\large{\sf{ \ratio\longmapsto{ - 50x= 85 - 340}}}}$

${\large{\sf{ \ratio\longmapsto{ - 50x= - 255}}}}$

Minus and Minus will be cancelled.

${\large{\sf{ \ratio\longmapsto{ 50x= 255}}}}$

Dividing 255 by 50.

${\large{\sf{ \ratio\longmapsto{ x= \cfrac{ 255}{50}}}}}$

Or value of x would be :-

$\underline{ \boxed{{\large{\bf{ \red{ \ratio\longmapsto{ x= \cfrac{ 51}{10} = { \boxed{5 \frac{1}{10} }} }}}}}}}$

____________________________________

VERIFICATION :-

It can be verified by putting in above equation.

${{\sf{ \ratio\longmapsto{ \cfrac{34}{5} \: \: - \: x = \cfrac{17}{10} }}}}$

${{\sf{ \ratio\longmapsto{ \cfrac{34}{5} \: \: - \: \cfrac{51}{10} = \cfrac{17}{10} }}}}$

${{\sf{ \ratio\longmapsto{ \cfrac{68 - 51}{10} = \cfrac{17}{10} }}}}$

${{\sf{ \ratio\longmapsto{ \cfrac{17}{10} = \cfrac{17}{10} }}}}$

Or

${{\sf{ \ratio\longmapsto{ 1.7 = 1.7 }}}}$

Here LHS = RHS

So, value of x is correct.