Question

step by step plz

10. A fruit-seller bought 75 kg mangoes at 30 per kg. He sold one-third man
should he sell the remaining so that his overall gain is 10%?
11. S.P. of 6 bananas is the same as the C.P. of 5 bananas. Find the gain or lo
12. A shopkeeper buys 5 fans for 4050. He spends 50 on the transportati
Find the selling price of a fan.​

Answer 1

10th :-

Given :-

• $\sf{\implies Fruitseller\: bought \: mangoes = 75\: kg}$

• $\sf{\implies Rate \: at \: which\: he \: bought = Rs\: 30\: per \: kg}$

• $\sf{\implies He \: sold\: \frac{1}{3} rd \: part\: of\: mangoes}$

To find :-

• $\sf{\implies \: At \: what \: rate \: mangoes\: should \:be \:sold\: to \: get\: 10 \: percent\: profit.}$

Solution :-

→ The Fruit seller purchased 75 kg mangoes = (75×30) rupees

$\sf{\implies Cost \: price \: = Rs\: 2250}$

→ He sold mangoes = $\sf{\frac{1\times 75}{3} \:kg}$

$\sf{\implies He \: sold\: 25\: kg }$

These 25 kg mangoes are sold at the same rate at which the fruit seller had purchased.

→ Amount of 25 kg mangoes = (25×30) rupees

$\sf{\implies 750 \: rupees }$

He wants to gain 10% . So Selling price is Rs 750 +X.......eq 1st

${\boxed{\sf{\implies \: Selling price \: = [ \frac{(100 + gain) }{100}] \times Cost price }}}$

${\sf{\implies \: Selling price \: = [ \frac{(100 + 10) }{100}] \times 2250 }}$

$\sf{\implies \: Selling price \: = [ \frac{\cancel \!110}{\cancel\!100}] \times \cancel{2250} = 11 \times 225 }$

${\boxed{\sf{\implies Rs \; 2475}}}$

Now we have to find out the value of x from eq 1st .

$\sf{\implies\:750 +x = 2475 }$

$\sf{\implies\: x = 2475 - 750}$

$\sf{\implies x = Rs \: 1725 }$

x is the cost of 50 kg fruits because 25 kg fruits were sold for Rs 750 .

Rate of 50 kg fruits = $\sf{\frac{1725}{50} = 34.5 \: Rupees }$

So fruit seller will sell his fruit for 34.5 rupees per kg for gaining 10%.

11th

Given :-

• S.P of 6 banana is equal to C.P of 5 bananas .

To find :-

• Gain or loss percentage

Solution :-

${\boxed{\sf{\Formula\: \frac{m-n}{n} \times 100 }}}$

Here m is C.P and n denotes S.P articles.

${\sf{\implies\: [ \frac{5-6}{6} \times 100] }}$

${\sf{\implies \: [ \frac{-100}{6} ] }}$

Negative sign show loss.

${\underline{\underline{\sf{\implies 16.67\: percent \; loss} }}}$

12th

Given :-

• Shopkeeper buys 5 fans .

• Total cost = Rs 4050 .

• 50 Rs transportation cost.

To find :-

• Total expenses .

Solution :-

Total expenses = Cost price + transportation cost

→ 4050 + 50 = Rs 5000.

The shopkeeper will sell the fans for amount amount greater than or equal to 5000 rupees .