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perpendicular line
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Given that :-
ABC is a equilateral triangle,in which AB = a, AC= a, or BC= a and angle ADC = 90 °
To find :-
AD
Proof :-
Now, In ∆ ADC, in which
AC = a
DC = a/2 ( because BC = BD + DC and BC = a, so DC= BD = a/2)
Now,
In ∆ ADC,
AC2 = AD2 + DC2 ( Using phythagerous theroem)
a2 = AD2 + a/2 2
a2 = AD2 + a2 /4
so, AD2 = a2 - a2 /4
AD2 = 4a2 /4 - a2 /4 ( By Taking LCM)
AD2 = 4a2 - a2/ 4
AD2 = 3a2 /4
or
AD = √ 3a2/4
AD = a/2 √ 3
Hence proved......
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