Question

Step by step solution

answer?​

Answer 1

Given – In ΔABC, AB = AC and a circle with AB as diameter is drawn Which intersects the side BC and D.

To prove – D is the mid point of BC

Construction – Join AD.

∴ By the right Angle – Hypotenuse – side criterion of congruence, we have

ΔABD ≅ ΔACD [ RHS criterion of congruence]

The corresponding parts of the congruent triangle are congruent.

∴ BD = DC [c.p.c.t]

Hence D is the mid point of BC.