Math, asked by jmdkrishna130475, 3 months ago

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Answered by roylily1958
2

Answer:

Let AB and AC be two chords and AOD be a diameter such that.

∠BAO = ∠CAO

Draw OL ⊥ AB and OM ⊥ AC

Now prove, ΔOLA = ΔOMA

Then OL = OM ⇒ AB = CD

(Chords which are equidistant from the centre are equal )

Hence proved.

Answered by Anonymous
13

Given:-

If two chords are equally Inclined to the diameter, i.e, <LAO = <MAO

OL Perpendicular to AB & OM Perpendicular to AC.

To Prove :-

AB = AC

Concept used :-

if the chords are equidistant from centre then the chords are equal.

Now,

In ∆OAL and ∆OAM

→ <OAL = <OAM ( given)

→ <OLA = <OMA = 90° ( given)

→AO = OA ( Common sides )

Thus, OAL OAM by ASA Congurency Criteria.

Therefore, By concept, AB = AC.

Hence, Proved.

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