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Let AB and AC be two chords and AOD be a diameter such that.
∠BAO = ∠CAO
Draw OL ⊥ AB and OM ⊥ AC
Now prove, ΔOLA = ΔOMA
Then OL = OM ⇒ AB = CD
(Chords which are equidistant from the centre are equal )
Hence proved.
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Given:-
If two chords are equally Inclined to the diameter, i.e, <LAO = <MAO
OL Perpendicular to AB & OM Perpendicular to AC.
To Prove :-
AB = AC
Concept used :-
if the chords are equidistant from centre then the chords are equal.
Now,
In ∆OAL and ∆OAM
→ <OAL = <OAM ( given)
→ <OLA = <OMA = 90° ( given)
→AO = OA ( Common sides )
Thus, ∆OAL ≈ ∆OAM by ASA Congurency Criteria.
Therefore, By concept, AB = AC.
Hence, Proved.
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