Question

step by step solution please help me
Q .5,6,7​

Answer 1

Step-by-step explanation:

Q-5

b+60°=180° (co-interior angle)

b= 180°-60°

b= 120°

a+b=180° ( linear pair)

a+120° = 180°

a= 180°-120°

a= 60°

a+c+ 50° = 180° (angle sum property of triangle)

60°+c+50° = 180°

110°+c = 180°

c= 180°-110°

c= 90°

Q-6

c and d are the triangles because their sum is 180°

Q-7

30°+32°+a = 180° (angle sum property of triangle)

62°+a = 180°

a= 180°-62°

a= 118°

a=b

b= 118°

c=32° (alternate interior angle)

d= 30° (alternate interior angle)

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Answer 2

Step-by-step explanation:

5) Since here two parallel lines l and m are cut by a traversal

• corresponding angles are equal
• alternate angles are equal
• adjacent angles are supplementary

Note:

In traingle always sum of all angles = 180°

angle a = 60°. (corresponding angles are equal)

angle a+ angle b = 180° (adjacent angles)

60+angle b = 180°

angle b = 180° - 60°

angle b = 120°

In traingle ADE

angle a+ angle c + angle AED = 180°

60° + angle c + 50° = 180°

angle c = 180° - 110°

angle c = 70°

6)Sum of all angles in traingle must be equal to 180°

so c) x=60° y= 60° z= 60°

60+60+60=180

here though d) sum is equal to 180 i.e, 90+90+0 it cannot form traingle as one of its angle is 0°

7) angle d = 30° (alternate angles )

angle c = 32° (alternate angles)

In traingle sum of all angles= 180

so, angle b + angle c+ angle d= 180

angle b + 32°+30°= 180

angle b = 180-62

angle b= 118°

angle a = angle b = 118 ( vertical opposite angle)

angle a = 118° ( or can also calculated by using sum of traingle)