Question

stepbrother borrowed rupees 28000 for 2 years the rate of interest for the two successive years are 8% and 10% respectively if he repairs Rupees 5240 at the end of the first year find the outstanding amount at the end of the second year​

Answer 1

Answer:

Rs.27500

Step-by-step explanation:

Amount at the end of 1st year =

$(28000 \times (1 + 8\div 100)) - 5240 \\ = (28000 \times 27 \div 25) - 5240 \\ = 25000$

Amount at the end of 2nd year =

$25000(1 + 10 \div 100) \\ = 27500$