Math, asked by bobandpetersphone, 8 months ago

Stephen, Gavin and Jim share some sweets in the ratio 4:1:2. Stephen gets 30 more sweets than Jim. How many sweets are there altogether?

Answers

Answered by ambarkumar1
2

Let thw sweets shared by Stephen, Gravin, and Jim be 4x, x and 2x respectively.

According to question

Stephen gets 30 more sweets than Jim.

4x = 30 + 2x

4x – 2x = 30

2x = 30

x = 15

Total no of sweets = 4x + x + 2x

= 7x

= 7 × 15

= 105

Answered by ankitphanzira
1

Answer:

105 sweets

Step-by-step explanation:

There are 4 + 1 + 2 = 7 parts in total

Stephen gets 4 parts (or 4x)

Jim gets gets 2 parts (or 2x)

Given,

Stephen gets 30 more than Jim, we can write:

Stephen = Jim + 30

or

4x = 2x + 30

We can solve for "x":

There are 7 parts of sweets altogether (or 7x), we know x so:

There are:

7 * 15 = 105 sweets altogether

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