Math, asked by WynetteC, 4 months ago

Stepp by step plzzzzzz!!!

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Answered by Anonymous
2

Answer:

Let’s say you have a toy car, and it’s sitting in front of a regular bathroom mirror. The distance between the car and mirror is called the object distance, and it’s always positive. If you look at the image of the toy car in the mirror, it will appear to be the same distance behind the mirror as the real car is in front of the mirror, at the same height. It will also appear to be the same size as the real car. The image of the car looks like it’s behind the mirror (and the light we see does not directly emerge from the image), we say that the image is upright and virtual, and that the image distance is negative.

Viewer and car on one side of the mirror, virtual car on the other side of the mirror with rays traced; dotted on virtual sideDistance covered in first 2 seconds = 10 m,

Body is in rest between 2 to 6 seconds so distance = 0 m,

Distance covered in first 6 to 8 seconds = 10 m,

Distance covered in first 8 to 10 seconds = 10 m,

Distance covered in first 10 to 12 seconds = 10 m,

So final distance = 10+10+10+10= 40 m.

Body is start at 0 seconds and comes to same position at 12th seconds so displacement is zero.

⇒ Distance = 40 m, Displacement = 0

Step-by-step explanation:

Answer:

Distance covered in first 2 seconds = 10 m,

Distance covered in first 2 seconds = 10 m,Body is in rest between 2 to 6 seconds so distance = 0 m,

Distance covered in first 2 seconds = 10 m,Body is in rest between 2 to 6 seconds so distance = 0 m,Distance covered in first 6 to 8 Seconds = 10 m,

= 10 m,Distance covered in first 8 to 10 seconds = 10 m,

= 10 m,Distance covered in first 8 to 10 seconds = 10 m,Distance covered in first 10 to 12 seconds = 10 m,

= 10 m,Distance covered in first 8 to 10 seconds = 10 m,Distance covered in first 10 to 12 seconds = 10 m,So final distance = 10+10+10+10= 40 m.

= 10 m,Distance covered in first 8 to 10 seconds = 10 m,Distance covered in first 10 to 12 seconds = 10 m,So final distance = 10+10+10+10= 40 m. Body is start at 0 seconds and comes to same position at 12th seconds so displacement is zero.

= 10 m,Distance covered in first 8 to 10 seconds = 10 m,Distance covered in first 10 to 12 seconds = 10 m,So final distance = 10+10+10+10= 40 m. Body is start at 0 seconds and comes to same position at 12th seconds so displacement is zero.⇒ Distance = 40 m, Displacement = 0Distance covered in first 2 seconds = 10 m,

Body is in rest between 2 to 6 seconds so distance = 0 m,

Distance covered in first 6 to 8 seconds = 10 m,

Distance covered in first 8 to 10 seconds = 10 m,

Distance covered in first 10 to 12 seconds = 10 m,

So final distance = 10+10+10+10= 40 m.

Body is start at 0 seconds and comes to same position at 12th seconds so displacement is zero.

⇒ Distance = 40 m, Displacement = 0Let’s say you have a toy car, and it’s sitting in front of a regular bathroom mirror. The distance between the car and mirror is called the object distance, and it’s always positive. If you look at the image of the toy car in the mirror, it will appear to be the same distance behind the mirror as the real car is in front of the mirror, at the same height. It will also appear to be the same size as the real car. The image of the car looks like it’s behind the mirror (and the light we see does not directly emerge from the image), we say that the image is upright and virtual, and that the image distance is negative.

Viewer and car on one side of the mirror, virtual car on the other side of the mirror with rays traced; dotted on virtual side

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