Question

Steps to solving this: If A+A=30, B+B=20, C+C =8, What is A+BXC?

Answer 1

Answer:

55

Step-by-step explanation:

$a + a = 30 \\ \\ 2a = 30 \\ \\ a = 15 \\ \\ b + b = 20 \\ \\ 2b = 20 \\ \\ b = 10 \\ \\ c + c = 8 \\ \\ 2c = 8 \\ \\ c = 4 \\ \\ a + b \times c = 15 + 10 \times 4 \\ \\ = 15 + 40 \\ \\ = 55.$

Answer 2

Step-by-step explanation:

A+A = 30

THE VALUE OF A IS 30/2 (SINCE A+A)

VALUE OF A = 15

B+B=20

THE VALUE OF B = 20/2 (SINCE B+B)

VALUE OF B = 10

C+C=8

THE VALUE OF C = 8/2 (SINCE C+C)

VALUE OF C = 4

NOW , A+B×C

BY SUBSTITUTING THEM ,

=15+10×4

=15+40

=55

THEREFORE, THE ANSWER IS 55

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