Question

Steve by step solve it just like a baby
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Answer 1

Hey mate forgive me if I make a mistake as the question is blur .

GIVEN::

•Mass of Moon - 7.3 ×10²² kg

•Radius of moon -1740 km=1.74 ×10^6m

•G = 6.7×10^-11 Nm/kg²

To find ::

Gravitational acceleration of Moon.

Formula ::

g = GM /R²

Solution::

g= (6.7×10^-11) × 7.3 ×10²² / (1.74 ×10^6)²

g= 6.7×7.3×10¹¹ / 1.74 ×1.74 × 10¹²

g= 48.91 × 10^-1 / 3.0276

g= 16.154 ×10^-1

g=1.615 m/sec²

Hope it helps brother ,,,,,

I've tried to solve it like a baby

not baby ..a baby can't solve it it's the boss baby XD

Ask if any doubt

Answer 2

Answer:1.63 m/s^2

Explanation: We know Accleration due to Gravity is given by

g= GM/R^2

Here the G= 6.67x10^-11

M=7.4x10^22

R=1740 km= 1740x10^3 m

Simply put these value in given formula

g= 6.67x10^-11 x 7.4x10^22/(1740x10^3)^2

= 0.001630268199x 10^3

= 1.630268199

= 1.63 m/s^2 (approximation)