Question

stion 4 Hindi
? The heat generated in a
bearing for given data will be
shaft dia= 150 mm. Speed is
1500 RPM, load = kN coefficient if
friction = 0.02 will be (formula =
mwv)​

Answer 1

Heat generated due to friction = 235.6 W

Explanation:

Given:

Load = Work = 1 kN = 1000 N

Co-efficient of friction, µ = 0.02

Speed N = 1500 RPM

Shaft diameter d = 150 mm = 0.15 m

Find: Heat generated.

Solution:  

Rubbing velocity V = πdN/60

= 22/7 * 0.15 * 1500 / 60

Heat generated due to friction, Qg = µ.W.V

 = 0.02 * 1000 * 11.78

 = 235.6 W