Question

stion is. Find pairs of consecutive odd numbers less than 10 whose sum is greater than 11.
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Answer 1

Answer:

Step-by-step explanation:

Let the two consecutive odd positive integer be xx and x+2x+2.

Both number are smaller than 10 Therefore

x+2<10

Adding −2−2 to both sides,

x<10−2

⇒x<8

Also sum of the two integers is more than 40.

So,x+x+2>40

⇒2x+2>40

adding −2to both sides,

2x>40−2

⇒2x>38

Divided by 2 both sides

x>19

Then the number greater then 10 and less then 19 are the consecutive odd number pair

In (C) (11,13),(13,15) ,(15,17) ,(17,19) is write answer