Question

stion pints) _ .. The position x of a particle varies with time t as x = at-bt2. The acceleration of the particle is ? ​

Answer 1

x=at2−bt3

⇒ Velocity =dtdx=2at−3bt2

Acceleration=dt2d2x=dtd(2at−3b2)=2a−6bt

or a=2a−6bt

Making a=0

⇒2a=6bt

⇒t=dfrac2a6b=3ba.