Question

Sto
c) 2.7 X 1024
Tome
2005 ETEA
(1 The number of oxygen atoms in 0.5
mole of Al2(CO3)3 is ..............
a) 4.5 x 10 23
b) 3.6 × 10 24
d) 9.0 10 23
2. Calculate the volume occupied by 2.8 g
of nitrogen gas at STP.
g​

Answer 1

Answer:

2.7×10^24

Explanation:

there are 9 moles of Oxygen in one mole of Al2 (CO3)3 . So in 0.5 moles of the compound, we have 4.5 moles . and no. of oxygen atoms =4.5×6.022×10^23= 27.0990 ×10^23= 2.7099×10^24 .

Answer 2

Answer:

don't no what is your answer