Question

stone is allowed to fall from the top of a tower hundred metres and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 metre by second calculate when and where the two stones will meet​

Answer 1

Answer:

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Answer 2

Answer

Let the stones meet at point A after time t.

For upper stone :

u′=0

x=0+21gt2

x=21×10×t2

⟹x=5t2 ............(1)

For lower stone :

u=25 m/s

100−x=ut−21gt2

100−x=(25)t−21×10×t2

⟹100−x=25t−5t2 ............(2)

Adding (1) and (2), we get

25t=100

⟹t=4 s

From (1),

x=5×42

⟹x=80 m

Hence the stone meet at a height of 20 m above the ground after 4 seconds.