Question

Stone is released from the top of a tower 19.6 m calculate the final velocity just before touching the

Answer 1

Answer:

v= 19.6m/s

Explanation:

Given

Initial Velocity(u)=0m/s(Stone was in rest before it was released)

Height(h)=19.6m

Gravitational force of Earth(g)=9.8m/s2

By using

$v {}^{2} = u {}^{2} + 2gh$

$v {}^{2} = 0 {}^{2} + 2 \times 9.8 \times 19.6$

$v = \sqrt{19.6 \times 19.6}$

v=19.6m/s

Hence Proved

Answer 2

Answer:

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