Question

stone is thrown vertically opposite of word with initial velocity of 50 m s with the maximum height reached by the stone what is the net displacement and the total displacement covered by the stone take G is equal to 10 metre per second square​

Answer 1

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.