stone of dropdown Jaideep well from rest the well is 50 M deep how long will it take to reach the bottom of the well give a is equal to 9.8 metre per second
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we know that
height of well= travelled distance by stone
[h ]= ut+½gt²
u=0
50=½*9.8.t²
or t²= 100/9.8
(t)time = 10/√9.8
height of well= travelled distance by stone
[h ]= ut+½gt²
u=0
50=½*9.8.t²
or t²= 100/9.8
(t)time = 10/√9.8
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