Physics, asked by sam09847, 7 months ago

stone of mass 10kg that is lifted to
a height of 8m if g=
1
10nky​

Answers

Answered by joshuaabrahamshomu
1

Answer:

Explanation:

Apparent weight =mg−F  

B

​  

 

where, F  

B

​  

 is buoyant force and mg is weight

We know that buoyant force F  

B

​  

 will be: F  B

​  

=Vρ  

water

​  

g=  

ρ  

stone  m  ρ  

water

​  

g

where V is volume of stone =  

ρ  

stone

​  

 

m

​  

 and  ρ  

water

​  

 is density of water

As specific gravity is given as 3 it's density will be three times of water

ρ  

water

​  

 

ρ  

stone

​  

 

​  

=3

Hence, F  B

​  =  3 mg

​  

 

Putting the values of m,g and applying the formula for work done,

Work done = Apparent weight × displacement

                   =10×g×h−  3 10×g ×h

                   =  3 2  ×10×10×6

                   =400 J

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