stone of mass 10kg that is lifted to
a height of 8m if g=
1
10nky
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1
Answer:
Explanation:
Apparent weight =mg−F
B
where, F
B
is buoyant force and mg is weight
We know that buoyant force F
B
will be: F B
=Vρ
water
g=
ρ
stone m ρ
water
g
where V is volume of stone =
ρ
stone
m
and ρ
water
is density of water
As specific gravity is given as 3 it's density will be three times of water
ρ
water
ρ
stone
=3
Hence, F B
= 3 mg
Putting the values of m,g and applying the formula for work done,
Work done = Apparent weight × displacement
=10×g×h− 3 10×g ×h
= 3 2 ×10×10×6
=400 J
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