Question

stone projected vertically up with velocity v from the top of a tower reaches the ground with
velocity 2. The height of the tower is
3v-​

Answer 1

Explanation:

Given, Velocity = 2v, Initial velocity = v.

We know that,

v² - u² = 2gh

=> (2v)² - (v)² = 2gh

=> 3v² = 2gh

=> h = (3v²/2g)

Hope it helps!

Answer 2

The height of the tower is 3v²/2g.

Given,

A stone is vertically projected upwards with velocity v and reaches the ground with velocity 2v.

To Find,

The height of the tower.

Solution,

By using the equation of motion

v²-u² = 2as

where,

v = final velocity = 2v

u = initial velocity = v

a = g acceleration due to gravity

s = distance traveled = height of the tower.

(2v)²-v² = 2gs

4v²-v² = 2gs

3v²/2g = s

Hence, the height of the tower is 3v²/2g.

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