Question

Stone was thrown horizontally at 25.0 m/s from a roof of a building lands 40.0 m from the base of the building. How tall is the building

Answer 1

horizontal distance=u√2h/g
$so \: 40 = 25 \times \sqrt{ \frac{2h}{g} } \\ \frac{40}{25} = \sqrt{ \frac{2h}{g} } \\ {( \frac{40}{25} )}^{2} = { \frac{2h}{g} } \\ 2.56 \times 9.8 = 2h \\ 25.088 \div 2 = h \\ 12.544 = h$
so height =12.544m
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