Question

Stopping distance for a car moving with a speed V
is x. If the car is moving with a speed 3V, then the
stopping distance will be
(1) √3x
(2) 3x
(3) 9x
(4) 27x​

Answer 1

Answer:

Answer is (3)

Explanation:

In case 1

initial velocity=v m/s

Vfinal. =0

distance=x m

from 3rd equation of motion

v^2=2as

a=v^2/2x. (constant)

In case. 2

v initial=3v

from 3rd equation

(3v)^2=2(v^2/2x)×S

9v^2=(v^2/x)×s

s=9x.

hence dist will be. 9x m (c)