Question

Stopping distance of a vehicles: when brakes are applied to a moving vehicle,the distance travel before stopping is called stoping distance. It is an important factor for road safety and depends on the initial velocity (vo) and the braking capacity or deceleration,-a that is caused by the braking . A car travelling at 72 km/hr suddenly applies a brake with a deaccleration of 5 m/s$^{2}$ . Find the stopping distance of the car.​

Answer 1

Correct Question:

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Stopping distance of a vehicles: when brakes are applied to a moving vehicle,the distance travel before stopping is called stoping distance. It is an important factor for road safety and depends on the initial velocity (${v_o}$) and the braking capacity or deceleration,-a that is caused by the braking . A car travelling at 72 km/hr suddenly applies a brake with a deaccleration of 5 m/s$^{2}$ . Find the stopping distance of the car.

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Answer:

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Stopping distance of the car will be 40 m.

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Explanation:

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Given:

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• Initial velocity (u) = 72 km/hr

• Final velocity (v) = 0

• Acceleration (a) = – 5m/s$^{2}$

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To find:

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Stoppind distance of the car.

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Solution:

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We know that

$v {}^{2} - u {}^{2} = 2as$

⟹ v$^{2}$ – u$^{2}$ = 2as

⟹ 0 = (20)$^{2}$ + 2 × (– 5) × s

⟹ 0 = 400 + (–10) × s

⟹ s = 40 m

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Thus, 40 m is the stopping distance of the car.