Stopping potentials of emitted photo electron is V when mono chromatic light of wavelength incident on a metal surface. If wavelength of light incident become 3 , stopping potential of photo electrons becomes V/4 then,the threshold wavelength of metal is k , then k will be :
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Given : stopping potential = V when a mono chromatic light of wavelength λ incident on the metal surface.
wavelength of incident light becomes 3λ, stopping potential becomes V/4.
To find : if threshold wavelength of metal is kλ, then value of k will be...
solution : using photoelectric effect, hc/λ - hc/λ₀ = K.E_{max} = eV₀
case 1 : threshold wavelength λ₀ = kλ
stopping potential, V₀ = V
so, hc/λ - hc/kλ = eV ........(1)
case 2 : wavelength, λ = 3λ
stopping potential, V₀ = V/4
so, hc/3λ - hc/kλ = eV/4 .........(2)
dividing equations (1) by (2) we get,
(1/λ - 1/kλ)/(1/3λ - 1/kλ) = 1/(1/4)
⇒1/λ - 1/kλ = 4/3λ - 4/kλ
⇒3/kλ = 1/3λ
⇒k = 9
Therefore the value of k = 9
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