Story on the topic taking a walk with friendly microbes you can take the reference of chapter microorganism and foe
Answers
Explanation:
Question 2.
Calculate the edge of the cube if its volume is 1331 cm3.
Solution:
Volume of cube = 1331 cm3
(Side)3 = 1331
Side = (11 × 11 × 11)13 = 11 cm
Question 3.
The curved surface area of a cone is 12320 sq. cm, if the radius of its base is 56 cm, find its
height.
Solution:
Here, radius of base of a cone (r) = 56 cm
And, curved surface area = 12320 cm2
πrl = 12320
l = 12320πr
= 12320×722×56 = 70 cm
Again, we have
r2 + h2 = l2
h2 = l2 – r2 = 702 – 562
= 4900 – 3136 = 1764
h = √1764 = 42 cm
Hence, the height of the cone is 42 cm.
Question 4.
Two cubes of edge 6 cm are joined to form a cuboid. Find the total surface area of the cuboid.
Solution:
When two cubes are joined end to end, then
Length of the cuboid = 6 + 6 = 12 cm
Breadth of the cuboid = 6 cm
Height of the cuboid = 6 cm
Total surface area of the cuboid = 2 (lb + bh + hl)
= 2(12 × 6 + 6 × 6 + 6 × 12)
= 2(72 + 36 + 72) = 2(180)
= 360 cm2
Question 5.
A metallic sphere is of radius 4.9 cm. If the density of the metal is 7.8 g/cm2, find the mass of the sphere (π = 227).
Solution:
Here, radius of metallic sphere (r) = 4.9 cm
The volume of a solid hemisphere is 1152 π cm3. Find its curved surface area.
Solution:
Here, volume of hemisphere = 1152 π cm3
∴ 23πr3 = 1152
⇒ r3 = (12)3 π
⇒ r1152×32 = 1728
⇒ r3 = (12)3
Now, curved surface area = 2πr2
= 2 × π × (12)2 = 288π cm2