Question

stp पर गैस 112a मेल आयतन का भाग 0.22 ग्राम है इस में अणुओं की संख्या कितनी है ? इस गैस का अनुभव कितना है​

Answer 1

Answer:

गैसों का अणुगति सिद्धान्त (kinetic theory of gases) गैसों के समष्टिगत (मैक्रोस्कोपिक) गुणों (दाब, ताप आदि) को समझने के लिये एक सरलीकृत मॉडल है। सार रूप में यह सिद्धान्त कहता है कि गैसों का दाब उनके अणुओं के बीच के स्थैतिक प्रतिकर्षण (static repulsion) के कारण नहीं है (जैसा कि न्यूटन का विचार था), बल्कि गतिशील अणुओं के आपसी टकराव (collision) का परिणाम है।

Answer 2

Given:

In STP,

The mass of an unknown sample of gas, m = 0.22 g

The volume of the unknown gas, V = 112 ml =  $\frac{112}{1000} \:L = 0.112\:L$

 

To find:

(i). How many molecules are there in the sample?

(ii) What is the molar mass of the gas?

Solution:

(i). Finding the moles in the given sample of gas:

We know,

At S.T.P → 1 mole of gas contains a volume of 22.4 L

and

1 mole of gas = 6.022 × 10²³ molecules/atoms/ions

We have a formula as:

 $\boxed{\bold{No.\: of\: moles, \:n = \frac{Volume\:(in\:litres)}{Volume\:of\:a\:gas\:at\:S.T.P} }}$

So, by substituting the values of the volumes, we get

n =   $\frac{0.112}{22.4} = 5\times 10^-^3\:moles$

Now,  

If 1 mole of a gas = 6.022 × 10²³ molecules

Then,

$5\times 10^-^3\:moles$ of the given sample is,  

=  $5\times 10^-^3 \times 6.022\times 10 ^2^3$

=  $30.11\times 10^2^0$

= $\bold{3.011\times 10^2^1\:molecules}$  

Thus, the no. of molecules in it is $\underline{3.011\times 10^2^1\:molecules}$.

(ii). Finding the molar mass of the given sample of gas:

We have a formula as:

$\boxed{\bold{No.\:of\:moles \:(n) = \frac{mass\: of \:gas\:(m)}{Molar\:mass\:of \:the\:gas\:(M)} }}$

Now, substituting the value if n = $5\times 10^-^3\:moles$ & m = 0.22 g in the formula above,

$5\times 10^-^3 = \frac{0.22}{M}$

$\implies M = \frac{0.22\:g}{5\times10^-^3\:mole}$

$\implies M = \frac{0.22\:g\times10^3}{5\:mole}$

 $\implies M = 0.044\times10^3\:g/mole}$

$\implies \bold{M = 44\:g/mole}$

 

Thus, the molar mass of the gas is $\underline{44\:g/mole}.$

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