Question

STRAIGHT LINE question !!

Find equation of line passing through (1,2) and (3,4)​

Answer 1

↪️STRAIGHT LINE ↩️

Let ( X1 - Y1 )= (1,2)

( X2 - Y2 ) = ( 3,4)

Equation of straight line =

$y - y1 = ( \frac{y2 - y1}{x2 - x1} )(x - x1) \\ \\ y - 2 = ( \frac{4 - 2}{3 - 1} )(x - 1) \\ \\ y - 2 = 1(x - 1) \\ \\ y = x + 1$

Equation of line is Y = X + 1

Answer 2

$\huge\star\underline\mathfrak\green{Hello \: Dear}\star$

$\huge\star\underline\mathfrak\purple{Answer}$

First you find the gradient of the line using the formula:

$\frac{y2 - y1}{x2 - x1}$

$\frac{4 - 2}{3 - 1} = \frac{2}{2} = 1$

Next, use the equation of a line which is

$(y - y1) = m(x - x1), where \: m \: is \: the \: gradient$

$(y - 2) = 1(x - 1) \:$

$y - 2 = x - 1 \:$

$Therefore, \:$

$y = x + 1 \:$