Question

straight lines represented by linear equations x-y=2 and 3x_2y=7 intersect at the point:-​

Answer 1

Answer:

2x + 5y = 12

We have,

x + y = 3

When y = 0 we have x = 3

When x = 0 we have y = 3

Thus we have the following table giving points on the line x + y = 3

X  0  3

Y  3  0

Now, 2 + 5y = 12

Step-by-step explanation:

this is the answer

Answer 2

Step-by-step explanation:

Given,

$x - y = 2 \\ x = y + 2$

and

$3x - 2y = 7$

Now,

$3(y + 2) - 2y = 7 \\ 3y + 6 - 2y = 7 \\ y + 6 = 7 \\ y = 1$

Now,

$x = y + 2 = 1 + 2 = 3$

Point is (3,1).

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