Question

straight lines

solve using disatnce form only

Answer 1

coordinates of BC is (2,0) & (0,2)
so from distance formula
side of equilateral triangle is
$= \sqrt{ {(x2- x1) }^{2} + {(y2 - y1) }^{2} } \\ = \sqrt{ {(2 - 2)}^{2} + {( - 1 - 1)}^{2} } \\ = \sqrt{ {0}^{2} + {2}^{2} } \\ = \sqrt{4} \\ = 2$
hope it helps