Physics, asked by tommyvecctery4624, 11 months ago

Strain energy of the stretched wire is 18×10^-3j and strain energy per unit volume of the same wire and the same cross section is 6×10^-3 j/m^3.calculate its volume​

Answers

Answered by aristocles
19

Answer:

Volume of the wire is 3 cubic meter

Explanation:

As we know that total strain energy stored in the wire is

U = 18 \times 10^{-3} J

now the energy density or total energy per unit volume of the wire is

\frac{U}{V} = 6 \times 10^{-3} J/m^3

now we know that

Volume = \frac{Energy}{Energy/Volume}

so we have

V = \frac{18\times 10^{-3}}{6 \times 10^{-3}}

V = 3 m^3

#Learn

Topic : Energy Density

https://brainly.in/question/2581335

Answered by CarliReifsteck
9

Answer:

The volume of the wire is 3 m³.

Explanation:

Given that,

Strain energy of stretched wire U=18\times10^{-3}\ J

Total energy per volume \dfrac{U}{V}= 6\times10^{-3}\ j/m^3

We need to calculate the volume of the wire

Using formula of volume

V=\dfrac{U}{\dfrac{U}{V}}

Where, U =Strain energy of the stretched wire

\dfrac{U}{V} = Energy per volume

Put the value into the formula

V=\dfrac{18\times10^{-3}}{6\times10^{-3}}

V=3\ m^3

Hence, The volume of the wire is 3 m³.

Learn more :

Topic : energy per volume

https://brainly.in/question/14339834

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