Chemistry, asked by shivaniardad2308, 8 months ago

Strain S:    CH3CH20H (aq)   +   H2O(aq)   →  CH3COO- (aq)  +  H+ (aq) +  2H2 (g)   (1)
Strain M.o.H.:     4H2 (g)  +   CO2 (g)   →   CH4 (g) +   2H2O  (aq)                               (2)

The critical point in this syntrophic cooperation is that the reaction that Strain S is catalyzing (Eq. 1) is only exergonic (negative ∆G0r ) if the H2 partial pressure (or the corresponding H2 concentration) in the aqueous phase is low enough. Hence, strain M.o.H. must remove hydrogen efficiently from the solution.

Calculate the maximum pH2 (H2 partial pressure) at which strain S can just gain some energy from catalyzing reaction Eq. 1 at pH 7 and 25o C, by assuming that both ethanol and acetate are present at a concentration of 10-6  M.​

Answers

Answered by kumarpawan86676
0

Answer:

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Explanation:

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