strated
A, B, and c can do a piece of work
in 1s, 12 and 20 days respectively. They sto
the work together, but c left after 2 days..
how many days will the remaining wook
be Completed by A and B ?
Answers
Answered by
1
Answer:
4
Step-by-step explanation:
T.w = LCM(15,12,20) = 60 units
their efficiency
A = 60/15 = 4 units/day
B = 60/12 = 5 u/day
C = 60/20 = 3 u/day
together in 1 day = 12 units
in 2 days = 2×12 = 24 units
remaining = 36 units
remaining work will complete in
= 36/ (4+5) = 4 days
Answered by
0
Answer:
Step-by-step explanation:
A can do a piece of work in 15 days
B can do same piece of work in 12 days
C can do same piece of work in 20 days
LCM of 15,12,20 = 60
Rate of A = 60/15 = 4 units/day
Rate of B = 60/12 = 5 units/day
Rate of C = 60/20 = 3 units/day
If all of them work together, work done per day = 4 + 5 + 3 = 12 units
For 2 days work done = 12x2=24 units
Work left after 2 days = 60 - 24 = 36 units
Time taken by A and B to complete = Work left / (rate of A+rate of B)=36/(5+4)=36/9=4 days
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