Question

String na="finder'; char s=na.charAt(4); char z =na.charAt(2);​

Answer 1

After Execution:

s = 'e'

z = 'n'

Answer 2

Question:-

Write the output of the following code.

Solution:-

Given,

String na="finder";

char s=na.charAt(4);

char z=na.charAt(2);

So,

s='e' (character at index 4 in variable na)

z='n' (character at index 2 in variable na)

Index value starts with 0.