Question

strings of a parachute can bear a maximum
tension of 72 kg wt. By what minimum
acceleration can a person of 96 kg descend by
means of this parachute ?​

Answer 1

Answer:

2.45 m/s²

Explanation:

Draw FBD

Net force while descending is

Fₙₑₜ = mg - T

Acceleration = Net force / Mass

= (mg - T)/(m)

= [(96 kg × 9.8 m/s²) - (72 kg × 9.8 m/s²)] / (96 kg)

= 2.45 m/s²