Question

Strong reducing behaviour of H₃PO₂ is due to [2015 RS]
(a) presence of one –OH group and two P–H bonds
(b) high electron gain enthalpy of phosphorus
(c) high oxidation state of phosphorus
(d) presence of two –OH groups and one P–H bond.

Answer 1

Answer:

Strong reducing behaviour of H₃PO₂ is due to [2015 RS]

(a) presence of one –OH group and two P–H bonds

(b) high electron gain enthalpy of phosphorus

(c) high oxidation state of phosphorus

(d) presence of two –OH groups and one P–H bond.

Answer 2

Presence of one –OH group and two P–H bonds is the correct option.

Explanation:

• Phosphorous is a group 15 element.

• It has 5 valance electrons.

• So the structure of H₃PO₂ has two PH bonds, one P-OH bond and one P O bond.

• Phosphorous is significantly electronegative.

• The addition of oxygen makes it even more electronegative and pulls the electron cloud.

• So phosphorous can easily leave the hydrogens from PH bond.

• So, it is highly reducing in nature.

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