Structure of a mixed oxide is ccp. The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral goods are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is:
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Answer:
AB2O2
Explanation:
It is given that the structure of mixed oxide is cubic closed packed.
Therefore, number of O^2- ions according to ccp =4
So, number of tetrahedral voids =8 and octahedral voids =4
A ions occupy 1/4th of tetrahedral voids =2
B ions occupy all octahedral voids =4
A:B:O =2:4:4 =1:2:2
Hence, the formula is AB2O2
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