Question

Structure of a mixed oxide is cubic close-packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One-fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is:​

Answer 1

Answer:

ANSWER

It is given that the structure of mixed oxide is cubic closed packed.

Therefore, number of O-2

ions according to ccp =4

So, number of tetrahedral voids =8 and octahedral voids =4

A ions occupy ¼ th of tetrahedral voids =2

B ions occupy all octahedral voids =4

A:B:O =2:4:4 =1:2:2

Hence, the formula is AB2O2

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Answer 2

Answer:

your answer is in attachment

Explanation:

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