Question

structure of the be(oh)42− anion

Answer 1

Explanation:

The Be(OH)42− anion present in Sr[Be(OH)4] has a fairly regular tetrahedral geometry for the central BeO4 unit with Be–O distances of 1.625(5) × 2 and 1.642(5) × 2 Å and O–Be–O bond angles in the range 106–116

Answer 2

Explanation:

The Be(OH)42− anion present in Sr[Be(OH)4] has a fairly regular tetrahedral geometry for the central BeO4 unit with Be–O distances of 1.625(5) × 2 and 1.642(5) × 2 Å and O–Be–O bond angles in the range 106–116°