Question

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Answer 1

Answer:

1/4 and ,123445|₹×358

Answer 2

Answer: 1) 4 +20ohm = 24 ohm

2) I(total current)= 6/24=1/4ampere

3) p.d across the lamp=1/4 *20=5volts

P.d across the conductor= 1/4*4=1 volt

4) power= 25/20 watt

Explanation: total resistance = sum of the two resistances in which are given in series as no internal resistance of the battery is mentioned so we would ignore that.

Total current through the circuit = total p.d/total resistance in the circuit and in this case we will take our terminal voltage as 6volt as no internal resistance is mentioned in the battery.

Potential difference across the lamp= current through the lamp and * resistance of lamp. Since the lamp is in series with the battery so the same. (I) current passed through it. Same logic for the conductor also.

•.• power= (voltage)^2/resistance of the lamp.