Question

studend A travels a distance 75m in 15 sec and student B
travels a distance of 80m in 20 sec, whose speed as more?​

Answer 1

Explanation:

see the pic I have solved...

Answer 2

Answer:

Let assume initial velocity is u and constant acceleration a. using s=ut + (0.5)at

2

,

for first 5 second

10 = 5u + (0.5)a(25)

for next 3 seconds, t=8 and s=20

20=8u+(0.5)a(64)

Solving,

a=

3

1

and u=

6

7

Now for next 2 seconds, t=10 and S

′

:

S

′

=(10)

6

7

+(0.5)

3

1

(100)

S

′

=

6

170

Now distance travelled in 2 sec =

6

170

−20=

6

50

meter