Physics, asked by sudheshna75, 5 months ago

student a travels a distance 75km in 15 sec and student b travels a distance of 80 m in 20 sec .whose speed is more

Answers

Answered by ntarun2006
1

Answer:

Student A

Explanation:

Distance travelled by student A = 75 km = (75*1000) m = 75000 m (Since 1 km = 1000 m)

Time taken = 15 sec

Speed = Distance/Time

= 75000/15

= 5000 m/s OR 5 km/s

Now,

Distance travelled by student B = 80 m

Time taken = 20 sec

Speed = Distance/Time

= 80/20

= 40 m/s

So, when we compare the speed of both students, we get the speed of Student A to be more.

Answered by vinaytiwary001
0

Answer:

for student a the distance equals to 75 km time equals to 15 seconds as we know that speed equals to distance upon time so first we need to convert 75 km in metres so 0.075 so sweet equals to distance upon time taken 0.075 upon 15 equals to 0.05 metre per second student be distance equals to 18 10-20 seconds speed equals to distance upon time taken equals 28120 equals to 4 metre per second student be travel

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