Question

student asked to make 20 gram of common salt and 320 gram of water in a beaker name the solution he will observe in the beaker after testing the mixture also calculate the number of moles of common salt present in solution ​

Answer 1

The student will observe a homogeneous salt solution.

Now, gram molecular mass of NaCl = (23+58.5) = 58.5

Hence, moles present in 20g of NaCl = 20/58.5

= 0.341880 (approx.)