student construted a triangle abc with sides ab=5cm, bc=6.5cm and ac=7cm and then constructed a ∆ade similar to ∆abc such that each of its sides are 7/ 5 of the corresponding sides of ∆abc.the length of ad and ae obtained by calculation are respectively equal to a 7cm and 9.8cm e b 5cm 6.5cm a c d
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Draw a line segment AB of 5cm.
Taking A and B as centre, draw arcs of 7cm and 6cm radius respectively.
Let these arcs intersect each other at point C.
Join AB and AC.
△ABC is the required triangle having length of sides as 5cm,7cm and 6cm respectively.
Step-by-step explanation:
Taking B as centre and radius 5 cm draw an arc. Taking C as centre and radius 7 cm, draw an arc which cut the previous arc at A. Join AB and AC. Thus, ABC is the required triangle
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