student focus the image of candle flame on screen of convex lens. he noted down; position of candle= 12 cm . 2)position of convex lens = 50 cm, 3)position of screen= 88 cm. find::- focal length of convex lens ii where image be formed if we shift candle at 31 cm. iii what will be the nature of image formed if e further shift the candle towards lens. draw ray diagram of image in third part
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A1) u=-(50-12) cm =-38 cm
& v=(88-50) cm=38 cm
using lens formula
1/v -1/u=1/f
1/38 -(-1/38)=1/f
1/f=1/19
f=19 cm
2) now
u=-(50-31) cm=-19 cm
so,
1/v-1/u=1/f
1/v=0
v=infinity
3) Now if candle is moved towards
lens the image will be magnified &
virtual & erect
& v=(88-50) cm=38 cm
using lens formula
1/v -1/u=1/f
1/38 -(-1/38)=1/f
1/f=1/19
f=19 cm
2) now
u=-(50-31) cm=-19 cm
so,
1/v-1/u=1/f
1/v=0
v=infinity
3) Now if candle is moved towards
lens the image will be magnified &
virtual & erect
anubhavsil137:
i think u have got ur answer
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