Question

Student focused the image of a candle flame on a white screen using a convex lens he noted down the position of the candle screen and the lens harjinder position of candle is equal to 2.0 cm position of convex lens is equal to 3.0 position of the screen 8.0 then what is the focal length of the convex lens not there will be the image be formed if the candle toward the lens at a position of 31.0 what will be the nature of the image formed if you for the ship the candle towards the lens draw a ray diagram to show the formation of the image in a case as said above

Answer 1

Answer:

Position of the candle flame = 12.0cm

Position of the lens= 50.0 cm

Position of the screen=88.0 cm

(i) the focal length of the convex lens.

(ii) Find the position of the image of the candle flame if it is shifted towards the lens at a position of 31.0 cm.

(iii) State the nature of the image formed if the candle flame is further shifted towards the lens.

(i) object distance u = position of convex lens - position of candle

U = -(50 -12) = -38 cm

image distance v = position of screen -position of convex lens

V-88-50 cm

v- 38 cm

Applying the lens formula:



On calculating focal length will be f-19 cm

(ii) When the candle is shifted towards the lens at a position of 31.0 cm:

Object distance u--(50-31)

U = -19 cm

Applying the lens formula



Therefore, v is infinity

(iii). If the candle is further shifted towards the lens, then the nature of the image formed will be virtual, erect and magnified

(iv) The ray diagram will be as follows: